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64x^2-24=30
We move all terms to the left:
64x^2-24-(30)=0
We add all the numbers together, and all the variables
64x^2-54=0
a = 64; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·64·(-54)
Δ = 13824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13824}=\sqrt{2304*6}=\sqrt{2304}*\sqrt{6}=48\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{6}}{2*64}=\frac{0-48\sqrt{6}}{128} =-\frac{48\sqrt{6}}{128} =-\frac{3\sqrt{6}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{6}}{2*64}=\frac{0+48\sqrt{6}}{128} =\frac{48\sqrt{6}}{128} =\frac{3\sqrt{6}}{8} $
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